jishu_2307400_1_1.html

前言

話說沒有藝術(shù)細胞的程序員不是好碼農(nóng)!

上一次我們進行了LCD的刷屏測試,我們覺得太單調(diào)了,程序員就應(yīng)該玩點有藝術(shù)性的。這次我們使用LCD點陣畫出各類具有藝術(shù)性的圖像。

參見https://codegolf.stackexchange.com/

代碼

有用到浮點算數(shù)運算,需要包含算術(shù)庫

#include

代碼如下

//圖片尺寸：

#define DIM 130

//圖片尺寸-1

#define DM1 (DIM-1)

#define _sq(x) ((x)*(x))                           // 平方

#define _cb(x) abs((x)*(x)*(x))                    // 立方的絕對值

#define _cr(x) (unsigned short)(pow((x),1.0/3.0))  // 立方根

 

unsigned char RD(int i,int j){

return (char)(_sq(cos(atan2(j-65,i-65)/2))*255);

}

 

unsigned char GR(int i,int j){

return (char)(_sq(cos(atan2(j-65,i-65)/2-2*acos(-1)/3))*255);

}

 

unsigned char BL(int i,int j){

return (char)(_sq(cos(atan2(j-65,i-65)/2+2*acos(-1)/3))*255);

}

 

unsigned char RD0(int i,int j)

{

float s=3./(j+99);

float y=(j+sin((i*i+_sq(j-700)*5)/100./DIM)*35)*s;

return ((int)((i+DIM)*s+y)%2+(int)((DIM*2-i)*s+y)%2)*127;

}

 

unsigned char GR0(int i,int j){

float s=3./(j+99);

float y=(j+sin((i*i+_sq(j-700)*5)/100./DIM)*35)*s;

return ((int)(5*((i+DIM)*s+y))%2+(int)(5*((DIM*2-i)*s+y))%2)*127;

}

 

unsigned char BL0(int i,int j){

float s=3./(j+99);

float y=(j+sin((i*i+_sq(j-700)*5)/100./DIM)*35)*s;

return ((int)(29*((i+DIM)*s+y))%2+(int)(29*((DIM*2-i)*s+y))%2)*127;

}

 

unsigned char RD1(int i, int j) {

#define r(n)(rand()%n)

    static char c[DIM][DIM]; return!c[i][j] ? c[i][j] = !r(999) ? r(256) : RD((i + r(2)) % 1024, (j + r(2)) % 1024) : c[i][j];

}

unsigned char GR1(int i, int j) {

    static char c[DIM][DIM]; return!c[i][j] ? c[i][j] = !r(999) ? r(256) : GR((i + r(2)) % 1024, (j + r(2)) % 1024) : c[i][j];

}

unsigned char BL1(int i, int j) {

    static char c[DIM][DIM]; return!c[i][j] ? c[i][j] = !r(999) ? r(256) : BL((i + r(2)) % 1024, (j + r(2)) % 1024) : c[i][j];

}

 

unsigned char RD2(int i, int j) {

    static double k; k += rand() / 1. / 0x7FFF; int l = k; l %= 512; return l > 255 ? 511 - l : l;

}

unsigned char GR2(int i, int j) {

    static double k; k += rand() / 1. / 0x7FFF; int l = k; l %= 512; return l > 255 ? 511 - l : l;

}

unsigned char BL2(int i, int j) {

    static double k; k += rand() / 1. / 0x7FFF; int l = k; l %= 512; return l > 255 ? 511 - l : l;

}

 

unsigned char RD3(int i, int j) {

    return (unsigned char)sqrt((double)(_sq(i - DIM / 2) * _sq(j - DIM / 2)) * 2.0);

}

unsigned char GR3(int i, int j) {

    return (unsigned char)sqrt((double)(

        (_sq(i - DIM / 2) | _sq(j - DIM / 2)) *

        (_sq(i - DIM / 2) & _sq(j - DIM / 2))

        ));

}

unsigned char BL3(int i, int j) {

    return (unsigned char)sqrt((double)(_sq(i - DIM / 2) & _sq(j - DIM / 2)) * 2.0);

}

 

unsigned char RD4(int i, int j) {

    static int r[DIM]; int p = rand() % 9 - 4; r[i] = i & r[i] ? (r[i] + r[i - 1]) / 2 : i ? r[i - 1] : 512; r[i] += r[i] + p > 0 ? p : 0; return r[i] ? r[i] < DIM ? r[i] : DM1 : 0;

}

unsigned char GR4(int i, int j) {

    static int r[DIM]; int p = rand() % 7 - 3; r[i] = i & r[i] ? (r[i] + r[i - 1]) / 2 : i ? r[i - 1] : 512; r[i] += r[i] + p > 0 ? p : 0; return r[i] ? r[i] < DIM ? r[i] : DM1 : 0;

}

unsigned char BL4(int i, int j) {

    static int r[DIM]; int p = rand() % 15 - 7; r[i] = i & r[i] ? (r[i] + r[i - 1]) / 2 : i ? r[i - 1] : 512; r[i] += r[i] + p > 0 ? p : 0; return r[i] ? r[i] < DIM ? r[i] : DM1 : 0;

}

 

void StartHdfSPITest(void)

{

    static uint16_t gcolor = 0xFFFF;

    LcdInit();

    while (1) {

        for(int i=0;ifor(int j=0;jstatic unsigned short color[3];

                color[0] = RD(i,j)&255;

                color[1] = GR(i,j)&255;

                color[2] = BL(i,j)&255;

                uint16_t c = (color[0]>>3) << 11;

                c |= (color[1]>>2) << 5;

                c |= (color[2]>>3) << 0;

                lcd_draw_point(i,j,c);

            }

        }

        LcdPush();

        LOS_Msleep(2000);

 

        for(int i=0;ifor(int j=0;jstatic unsigned short color[3];

                color[0] = RD1(i,j)&255;

                color[1] = GR1(i,j)&255;

                color[2] = BL1(i,j)&255;

                uint16_t c = (color[0]>>3) << 11;

                c |= (color[1]>>2) << 5;

                c |= (color[2]>>3) << 0;

                lcd_draw_point(i,j,c);

            }

        }

        LcdPush();

        LOS_Msleep(2000);

 

        for(int i=0;ifor(int j=0;jstatic unsigned short color[3];

                color[0] = RD2(i,j)&255;

                color[1] = GR2(i,j)&255;

                color[2] = BL2(i,j)&255;

                uint16_t c = (color[0]>>3) << 11;

                c |= (color[1]>>2) << 5;

                c |= (color[2]>>3) << 0;

                lcd_draw_point(i,j,c);

            }

        }

        LcdPush();

        LOS_Msleep(2000);

 

        for(int i=0;ifor(int j=0;jstatic unsigned short color[3];

                color[0] = RD3(i,j)&255;

                color[1] = GR3(i,j)&255;

                color[2] = BL3(i,j)&255;

                uint16_t c = (color[0]>>3) << 11;

                c |= (color[1]>>2) << 5;

                c |= (color[2]>>3) << 0;

                lcd_draw_point(i,j,c);

            }

        }

        LcdPush();

        LOS_Msleep(2000);

 

        for(int i=0;ifor(int j=0;jstatic unsigned short color[3];

                color[0] = RD4(i,j)&255;

                color[1] = GR4(i,j)&255;

                color[2] = BL4(i,j)&255;

                uint16_t c = (color[0]>>3) << 11;

                c |= (color[1]>>2) << 5;

                c |= (color[2]>>3) << 0;

                lcd_draw_point(i,j,c);

            }

        }

        LcdPush();

        LOS_Msleep(2000);

    }

}
;j++)>;i++)>;j++)>;i++)>;j++)>;i++)>;j++)>;i++)>;j++)>;i++)>

效果

總結(jié)

代碼中有大量的浮點運算,本身也可以作為CPU性能的一個對比測試,同時也可以測試刷屏的速率。從效果來看CPU的性能是不錯的,刷頻效果也可以,后面就正式開始LVGL的移植了。

聲明：本文內(nèi)容及配圖由入駐作者撰寫或者入駐合作網(wǎng)站授權(quán)轉(zhuǎn)載。文章觀點僅代表作者本人，不代表電子發(fā)燒友網(wǎng)立場。文章及其配圖僅供工程師學(xué)習(xí)之用，如有內(nèi)容侵權(quán)或者其他違規(guī)問題，請聯(lián)系本站處理。舉報投訴